\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{12}=\dfrac{4}{12}+\dfrac{2}{12}+\dfrac{1}{12}=\dfrac{4+2+1}{12}=\dfrac{7}{12}\)
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\(\dfrac{1}{3}+\dfrac{1}{6}+\dfrac{1}{12}=\dfrac{4}{12}+\dfrac{2}{12}+\dfrac{1}{12}=\dfrac{4+2+1}{12}=\dfrac{7}{12}\)