Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Các câu hỏi tương tự
tìm x:\(\frac{32}{8.11}+\frac{32}{11.14}+\frac{32}{14.17}+...+\frac{32}{197.200}-x=\frac{1}{2}\)
F=32/8.11 +32/ 11.14 + 32/ 14.17+...+ 32/197.200
E 1/25.27+1/27.29+1/29.31 +...+1/73.75
G =15/90.94+15/94.98 +15/98.102 +....+15/146.150
H=10/56+10/140 +10/260+....+10/1400
Tính tổng: \(B=\frac{3^2}{8.11}+\frac{3^2}{11.14}+\frac{3^2}{14.17}+...+\frac{3^2}{197.200}\)
Tính tổng sau :
C=32/8.11 + 32/11.14 + 32/14.17 + ...... + 32/197.200
Tính tổng
B=32/8.11 +32/11.14+32/14.17+...+32/197.200
\(\dfrac{3^2}{8.11}+\dfrac{3^2}{11.14}+\dfrac{3^2}{14.17}+....+\dfrac{3^2}{197.200}\)
TÝnh:
N = 32/8.11 + 32/11.14 + 32/14.17 + ...+32/197.200.
\(\frac{3^2}{8.11}\) +\(\frac{3^2}{11.14}\)+\(\frac{3^2}{14.17}\)+...+\(\frac{3^2}{197.200}\)
[\(\frac{2000}{2000.2006}+\frac{2000}{2006.2012}+\frac{2000}{2012.2018}+.....+\frac{2000}{2492.2498}\)]x\(\frac{^{3^2}}{8.11}+\frac{3^2}{11.14}+\frac{3^2}{14.17}+.....+\frac{3^2}{197.200}\)