\(2+4+6+8+...+150=\frac{\left(150+2\right)\left[\left(150-2\right)\div2+1\right]}{2}\)
\(=\frac{152.75}{2}=76.75=5700\)
\(7+10+13+...+76=\frac{\left(76+7\right)\left[\left(76-7\right)\div3+1\right]}{2}\)
\(=\frac{83.24}{2}=83.12=996\)
\(49+64+81+...+169=7^2+8^2+9^2+...+13^2=584\)