Question

TÍNH TỔNG SAU A=3²/8.11+3²/11.14+...+3²/1997.2000

Answer 1

=3(\(\frac{3}{8.11}\)+\(\frac{3}{11.14}\)+...+\(\frac{3}{1997.2000}\))

=3(\(\frac{1}{8}\)-\(\frac{1}{11}\)+\(\frac{1}{11}\)-\(\frac{1}{14}\)+...+\(\frac{1}{1997}\)-\(\frac{1}{2000}\))

=3(\(\frac{1}{8}\)-\(\frac{1}{2000}\))=3.\(\frac{249}{2000}\)=\(\frac{747}{2000}\)

Answer 2

\(A=3.\left(\frac{3}{8.11}+\frac{3}{11.14}+...+\frac{3}{1997.2000}\right)\)

\(=3.\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{1997}-\frac{1}{2000}\right)\)

\(=3.\left(\frac{1}{8}-\frac{1}{2000}\right)\)

\(=3.\frac{249}{2000}\)

\(\frac{747}{2000}\)

Answer 3

A = 3 (3 / 8.11 + 3 / 11.14 + ..... + 3/1997.2000)

A = 3.(1/8 - 1/11 + 1/11 - 1/14 +........+1/1997 - 1/2000)

A = 3.(1/8 - 1/2000)

A = 3 .249/2000

A = 747/2000

Answer 4

k cho bạn đi

Answer 5

\(=\frac{474}{2000}\)