Đáp án B
Ta có 1 + x 2018 = ∑ k = 0 2018 C 2018 k x k = C 2018 0 + C 2018 1 x + ... + C 2018 2018 x 2018 .
Chọn x = 1 ⇒ 2 2018 = C 2018 0 + C 2018 1 + ... + C 2018 2018 .
Vì C n k = C n n − k ⇒ 2 2018 = 2 C 2018 1010 + C 2018 1011 + C 2018 2018 + C 2018 1009 = 2 S + C 2018 1009 ⇒ S = 2 2017 + 1 2 C 2018 1009 .