Question

Tính phân tử khối của các phân tử sau:

CO₂, HNO₃, Fe(OH)₃, CuO, Fe₂(S0₄)₃, NaNO₃; K₂CO₃

Answer 1

\(PTK_{CO_2}=12+2\cdot16=44\left(đvC\right)\)

\(PTK_{HNO_3}=1+14+3\cdot16=63\left(đvC\right)\)

\(PTK_{Fe\left(OH\right)_3}=56+3\cdot16+3=107\left(đvC\right)\)

\(PTK_{CuO}=64+16=80\left(đvC\right)\)

\(PTK_{Fe_2\left(SO_4\right)_3}=2\cdot56+3\cdot32+12\cdot16=400\left(đvC\right)\)

\(PTK_{NaNO_3}=23+14+3\cdot16=85\left(đvC\right)\)

\(PTK_{K_2CO_3}=2\cdot39+12+3\cdot16=138\left(đvC\right)\)