\(\frac{2016\times2018+2}{2016\times2017+2018}=\frac{2016\times\left(2017+1\right)+2}{2016\times2017+2018}=\)\(=\frac{2016\times2017+2016+2}{2016\times2017+2018}=\frac{2016\times2017+2018}{2016\times2017+2018}=1\)
Ta có : \(\frac{2016\times2018+2}{2016\times2017+2018}=\frac{2016\left(2017+1\right)+2}{2016\times2017+2018}=\frac{2016\times2017+2016+2}{2016\times2017+2018}\)
\(=\frac{2016\times2017+2018}{2016\times2017+2018}=1\)
2016x(2016+2)+2016-2014 2016x2016+2x2016+2016-2014 2019 x 2016 - 2014 2019 x 2016 - 2016 + 2 2018 x 2016+2
_____________________ =____________________________= ________________=___________________=____________= 1
2016x(2016+1)+2016+2 2016 x 2016 + 1 x 2016 + 2016 + 2 2018 x 2016 + 2 2018 x 2016 +2 2018 x 2016 +2