Đặt B=1+2+3+...+100
B có: (100-1)+1=100(số hạng)
B=(100+1)*100/2=5050
nên -B=C=-(1+2+3+...+100)=-1-2-3-...-100=-5050
-(1+2+3+4+.....+100)
-[(100+1).100:2]
-5050
Nho tick nha
Đặt B=1+2+3+...+100
B có: (100-1)+1=100(số hạng)
B=(100+1)*100/2=5050
nên -B=C=-(1+2+3+...+100)=-1-2-3-...-100=-5050
-(1+2+3+4+.....+100)
-[(100+1).100:2]
-5050
Nho tick nha
Bài3 tính nhanh
c. 456:2x 18+456:3-102
bài 4 tìm số tự nhiên n sao cho
121/27x 54/11<n<100/21:25/126
Bài5
x/17=60/204 6+x/33=7/11 12+x/43-x=2/3
x/5<3/7 1<11/x<2 15/26+x/16=46/52
bài6 tính nhanh
21,251+6,058+0,749+1,042 1,53+5,309+12,47+5,691
Tính C=1/2-(1/3+2/3)+(1/4+2/4+3/4)-(1/5+2/5+3/5+4/5)+...+(1/100+2/100+...+99/100)
B=1 + 3/ 2^3 + 4/2^4 + 5/2^5+ ... + 100/2^100
Tính B
1, Tính \(\frac{1}{2}-\left(\frac{1}{3}+\frac{2}{3}\right)+\left(\frac{1}{4}+\frac{2}{4}+\frac{3}{4}\right)-\left(\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}\right)+...+\left(\frac{1}{100}+\frac{2}{100}+\frac{3}{100}+...+\frac{99}{100}\right)\)2,Tính \(\left(1-\frac{1}{2^2}\right)x\left(1-\frac{1}{3^2}\right)x\left(1-\frac{1}{4^2}\right)x...x\left(1-\frac{1}{n^2}\right)\)
tính nhanh
A=(1^100+2^100+…+10^100).(5^10-25^5)
B=(2^5+3^5+4^5).(1^2+2^2+…+100^2).(4^10-2^20)
Bài 4: Tính tổng 1) 1 + (-2) + 3 + (-4) + . . . + 19 + (-20) 2) 1 – 2 + 3 – 4 + . . . + 99 – 100 3) 2 – 4 + 6 – 8 + . . . + 48 – 50 4) – 1 + 3 – 5 + 7 - . . . . + 97 – 99 5) 1 + 2 – 3 – 4 + ... + 97 + 98 – 99 - 100
1,tính :
a, 1+2+3+4+5+........+99+100
b, 1+( -2 )+3+( -4)+5 +.........+99+( -100)
Bài 1: Tính A=\(1+2+2^2-2^3+2^4-2^5+......+2^{98}+2^{99}+2^{100}\)\(2^{100}\)
Bài 2: Tính D=\(1-3^2+3^3-3^4+3^5+...-3^{100}+3^{101}\)
1, tính :
a, 1+2+3+4+5+6+ .......+99+100
b, 1+( -2) +3+(-4) +5 +.......+99+( -100)
Tính:
\(\frac{1}{2}-\left(\frac{1}{3}+\frac{2}{3}\right)+\left(\frac{1}{4}+\frac{2}{4}+\frac{3}{4}\right)-\left(\frac{1}{5}+\frac{2}{5}+\frac{3}{5}+\frac{4}{5}\right)+...+\left(\frac{1}{100}+\frac{2}{100}+\frac{3}{100}+...+\frac{99}{100}\right)\)