a,\(\frac{31}{17}+\frac{5}{13}+\frac{8}{13}-\frac{14}{17}=\left(\frac{31}{17}-\frac{14}{17}\right)+\left(\frac{5}{13}+\frac{8}{13}\right)=1+1=2\) b,\(\frac{5}{7}.\frac{22}{11}+\frac{5}{7}.\frac{9}{11}+\frac{5}{7}=\frac{5}{7}.\left(\frac{22}{11}+\frac{9}{11}+1\right)=\frac{5}{7}.4=\frac{20}{7}\)
a) \(\frac{31}{17}+\frac{5}{13}+\frac{8}{13}-\frac{14}{17}\)
\(=\left(\frac{31}{17}-\frac{14}{17}\right)+\left(\frac{5}{13}+\frac{8}{13}\right)\)
\(=1+1\)
\(=2\)
b) \(\frac{5}{7}\cdot\frac{22}{11}+\frac{5}{7}\cdot\frac{9}{11}+\frac{5}{7}\)
\(=\frac{5}{7}\cdot\left(\frac{22}{11}+\frac{9}{11}+1\right)\)
\(=\frac{5}{7}\cdot\frac{42}{11}\)
\(=\frac{30}{11}\)