\(\frac{2^{83}+2^{84}+2^{85}}{2^{82}+2^{81}+2^{80}}=\frac{2^{83}.\left(1+2+2^2\right)}{2^{80}.\left(2^2+2+1\right)}=2^3=8\)
\(\frac{2^{83}+2^{84}+2^{85}}{2^{82}+2^{81}+2^{80}}=\frac{2^{80}.2^3+2^{80}.2^4+2^{80}+2^5}{2^{80}.1+2^{80}.2^2+2^{80}.2^3}=\frac{2^{80}.\left(8+16+32\right)}{2^{80}.\left(1+4+8\right)}=\frac{56}{13}\)