Question

tính nhanh giá trị biểu thức 

a)\(2^{78}+2^{79}+2^{80}:2^{77}+2^{76}+2^{75}\)

 

 

 

giupd mình với

Answer 1

\(\left(2^{78}+2^{79}+2^{80}\right):\left(2^{77}+2^{76}+2^{75}\right)\)

\(=2^3\left(2^{75}+2^{76}+2^{77}\right):\left(2^{75}+2^{76}+2^{77}\right)\)

\(=2^3\)

\(=8\)

Answer 2

Bài làm:

\(\left(2^{78}+2^{79}+2^{80}\right)\div\left(2^{77}+2^{76}+2^{75}\right)\)

\(=\frac{2^{78}\left(1+2+2^2\right)}{2^{75}\left(2^2+2+1\right)}\)

\(=2^3=8\)

Answer 3

=(2⁷⁸+2⁷⁹+2⁸⁰):(2⁷⁷+2⁷⁶+2⁷⁵)
=2³

Answer 4

\(2^{78}+2^{79}+2^{80}:2^{77}+2^{76}+2^{75}\)

\(=\frac{2^{78}.\left(1+2+2^2\right)}{2^{75}.\left(2^2+2+1\right)}\)

\(=\frac{2^{78}}{2^{75}}\)

\(=2^{78}:2^{75}\)

\(=2^3=8\)

Answer 5

Thanks