\(\frac{1}{2}+\frac{2}{4}+\frac{3}{6}+\frac{4}{8}\)
\(=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{2}{2}\)
\(=\frac{1}{2}\times4\)
\(=2\)
\(\frac{1}{2}+\frac{2}{4}+\frac{3}{6}+\frac{4}{8}\)
= \(\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}\)
= \(\frac{1}{2}.4\)
= 2
\(\frac{1}{2}+\frac{2}{4}+\frac{3}{6}+\frac{4}{8}=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+\frac{1}{2}=\frac{1}{2}\cdot4=2\)
\(\frac{1}{2}\)+\(\frac{2}{4}\)+\(\frac{3}{6}\)+\(\frac{4}{8}\)
= \(\frac{1}{2}\)+\(\frac{1}{2}\)+\(\frac{1}{2}\)+\(\frac{1}{2}\)= \(\frac{4}{2}\)=2