\(A=28\left(\frac{7}{2008}+\frac{2001}{2008}\right)+\frac{2008}{2009}+\frac{1}{2009}=28+1+1=30\)
\(A=28\frac{7}{2008}+\frac{2008}{2009}+\frac{2001}{2008}+\frac{1}{2009}=\left(28+\frac{7}{2008}+\frac{2001}{2008}\right)+\left(\frac{2008}{2009}+\frac{1}{2009}\right)=29+1=30\)