a)2/3*4/7+1/3*4/7=(2/3+1/3)*4/7=1*4/7=4/7
b)5/8*3/7*7/3=5/8*1=5/8
c)(4/5+2)*5/4=4/5*5/4+2=1+2=3
a,Ta có:(\(\frac{2}{3}\)+\(\frac{1}{3}\)) x \(\frac{4}{7}\)
=1 x \(\frac{4}{7}\)
= \(\frac{4}{7}\)
b,Ta có:\(\frac{5}{8}\) x (\(\frac{3}{7}\) x \(\frac{7}{3}\))
=\(\frac{5}{8}\) x 1
=\(\frac{5}{8}\)
c,Ta có:\(2\frac{4}{5}\) x \(\frac{5}{4}\)
= (\(\frac{4}{5}\) x \(\frac{5}{4}\)) x ( 2 x 1)
= 1 x 2
= 2
a, 2/3 x 4/7 + 1/3 x 4/7
= ( 2/3 x 1/3 ) + ( 4/7 x 4/7 )
= 3/3 + 8/7
= 1 + 8/7
= 15/7
câu c mình làm sai: ta có:\(\frac{4}{5}\) x \(\frac{5}{4}\) + 2 x \(\frac{5}{4}\)
=1 + \(\frac{5}{2}\)
= \(\frac{7}{2}\)