`A=3 + 3/5 + 3/25 + 3/125 + 3/625`
`5A=5 xx (3+3/5+3/25+3/125+3/625)`
`5A= 15+3+3/5+3/25+3/125`
`5xxA-A=(15+3+3/5+3/25+3/125)-(3+3/5+3/25+3/125+3/625)`
`(5-1)xxA=15+3+3/5+3/25+3/125-3-3/5-3/25-3/125-3/625`
`4 xx A=(15-3/625)+(3-3)+(3/5-3/5)+(3/125-3/125)`
`4 xx A=9372/625+0+0+0+0`
`A=2343/625`