\(=\dfrac{2}{3}+\left(\dfrac{5}{7}+\dfrac{-2}{3}\right)=\left[\dfrac{2}{3}+\dfrac{-2}{3}\right]+\dfrac{5}{7}\\ =0+\dfrac{5}{7}=\dfrac{5}{7}\)
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\(\dfrac{2}{3}+\left(\dfrac{5}{7}+\dfrac{-2}{3}\right)=\dfrac{2}{3}+\dfrac{5}{7}+\dfrac{-2}{3}=\left(\dfrac{2}{3}+\dfrac{-2}{3}\right)+\dfrac{5}{7}=0+\dfrac{5}{7}=\dfrac{5}{7}\)
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