Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Tính nhanh:
\(\frac{2}{3}+\frac{14}{15}+\frac{34}{35}+\frac{62}{63}+...+\frac{9998}{9999}\)
\(\frac{2}{3}+\frac{14}{15}+\frac{34}{35}+\frac{9998}{9999}\)
Tính M= 2/3+14/15+34/35+62/63+...+9998/9999
Tìm A :
1 / A = ( 1 -\(\frac{1}{3}\)) + ( 1 - \(\frac{1}{15}\)) + ( 1 - \(\frac{1}{35}\)) + ( 1 - \(\frac{1}{63}\))
2 / A = ( 1 -\(\frac{1}{10}\)) + ( 1 - \(\frac{1}{40}\)) + ( 1 - \(\frac{1}{88}\)) + ( 1 - \(\frac{1}{154}\))
3 / A = \(\frac{2}{3}+\frac{14}{15}+\frac{34}{35}+....+\frac{9998}{9999}\)
4 / A = \(\frac{9}{10}+\frac{39}{40}+\frac{87}{88}+...+\frac{1119}{1120}\)
5 / A = \(\frac{9}{10}+\frac{39}{40}+\frac{87}{88}+\frac{153}{154}\)
Trình bày cách làm hộ mình nha ! Cảm ơn rất nhiều !
a/ 1/2 + 5/6 + 11/12 + 19/20
b/ 1/2 + 5/6 + 11/12 + 19/20 + 29/30 + 41/42
c/ (1-1/3) + (1-1/15) + (1-1/35) + (1-1/63)
d/ 1/2 + 5/6 + 11/12 + ... + 9899/9900
e/ 2/3 + 14/15 + 34/35 +62/63
f/ 2/3 + 14/15 + 34/35 + ... + 9998/9999
\(A=\frac{3}{2}+\frac{7}{6}+\frac{13}{12}+\frac{21}{20}+...+\frac{13}{53}\)\(B=\frac{16}{15}+\frac{36}{35}+\frac{63}{63}+...+\frac{10000}{9999}\)
\(Giải-giúp-mk-nha\)
Giúp mình với!
\(\left(\frac{9998}{9999}.\frac{11}{17}+\frac{9998}{9999}.\frac{7}{24}-\frac{19996}{19998}\right):\left(5\frac{11}{17}+\frac{7}{24}-6\right)\)
Tính Nhanh các tổng sau:
\(M=\frac{1}{2}+\frac{1}{14}+\frac{1}{35}+\frac{1}{65}+\frac{1}{104}+\frac{1}{152}\)
\(N=\frac{1}{15}+\frac{1}{35}+\frac{1}{63}+\frac{1}{99}+\frac{1}{143}\)
Bài 1: So sánh:
A=\(\frac{2}{3}\)+ \(\frac{14}{15}\)+ \(\frac{34}{35}\)+ \(\frac{62}{63}\)+ \(\frac{98}{99}\)+ \(\frac{142}{143}\)+ \(\frac{194}{195}\)
B= 5+ \(\frac{1}{2^2}\)+ \(\frac{1}{3^3}\)+ \(\frac{1}{4^4}\)+ \(\frac{1}{5^5}\)+ \(\frac{1}{6^6}\)+ \(\frac{1}{7^7}\)
Bài 2: Chứng minh:
C=\(\frac{1}{5}\)+ \(\frac{1}{13}\)+ \(\frac{1}{14}\)+ \(\frac{1}{15}\)+ \(\frac{1}{61}\)+\(\frac{1}{62}\)+ \(\frac{1}{63}\)< \(\frac{1}{2}\)
