\(\left(\frac{81}{12}-\frac{9}{4}\right).\left(\frac{2}{9}\right)^2-\frac{2}{9}\)
\(=\left(\frac{27}{4}-\frac{9}{4}\right).\frac{4}{81}-\frac{2}{9}\)
\(=\left(\frac{27}{4}-\frac{9}{4}\right).\frac{4}{81}-\frac{2}{9}\)
\(=\frac{9}{2}.\frac{4}{81}-\frac{2}{9}\)
\(=\frac{9.4}{2.81}-\frac{2}{9}\)
\(=\frac{1.2}{1.9}-\frac{2}{9}\)
\(=\frac{2}{9}-\frac{2}{9}=0\)
\(\left(\frac{81}{12}-\frac{9}{4}\right).\left(\frac{2}{9}\right)^2-\frac{2}{9}\)
\(=\left(\frac{27}{4}-\frac{9}{4}\right).\left(\frac{2}{9}.\frac{2}{9}\right)-\frac{2}{9}\)
\(=\frac{9}{2}.\frac{4}{81}-\frac{2}{9}\)
\(=\frac{9.4}{2.81}-\frac{2}{9}=\frac{2}{9}-\frac{2}{9}=0\)
Vậy \(\left(\frac{81}{12}-\frac{9}{4}\right).\left(\frac{2}{9}\right)^2-\frac{2}{9}=0\)
bỏ cho mk dòng bị dư nha