Question

Tính khối lượng theo đơn vị gam của 1 nguyên tử nguyên tố sau: O, S, Ca, Zn, Fe

Answer 1

n_{Mỗi nguyên tố} =\(\frac{1}{6.10^{23}}\left(mol\right)\)

m\(_O=16.\frac{1}{6,10^{23}}=\left(g\right)\)

m\(_S=\frac{32.1}{6.10^{23}}\left(g\right)\)

m\(_{Ca}=\frac{40}{6.10^{23}}\)

m\(_{Zn}=\frac{65}{6.10^{23}}\)

m\(_{Fe}=\frac{56}{6,10^{23}}\)

Tự tính ra kết quả nha

Answer 2

https://i.imgur.com/61BEZdD.jpg

Answer 3

https://i.imgur.com/y7NsU9j.jpg

Answer 4

\(1đvc=1,6605.10^{-24}\)

Công thức:\(1,6605.10^{-24}\) nhân cho NTK của nguyên tố

\(\Rightarrow mO=1,6605.10^{-24}.16=2.6568.10^{-23}\left(g\right)\)

\(\Rightarrow mS=1,6605.10^{-24}.32=5,3136.10^{-23}\left(g\right)\)

\(\Rightarrow\text{mCa=1.6605.10}^{-24}.40=6.624.10^{-23}\left(g\right)\)

\(\Rightarrow mZn=1,6605.10^{-24}.65\simeq1.08.10^{-22}\left(g\right)\)

\(\Rightarrow mFe=1,6605.10^{-24}.56=9.2988.10^{-23}\left(g\right)\)