\(a,=\left(\dfrac{0,8}{0,4}\right)^5\cdot0,8=2^5\cdot0,8=32\cdot0,8=25,6\\ b,=\dfrac{2^{15}\cdot3^8}{2^3\cdot3^3\cdot2^9}=2^3\cdot3^5=1944\\ c,=\dfrac{2^{30}+2^{20}}{2^{12}+2^{22}}=\dfrac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}=2^8=256\)