`a, = (3^20 . 5^20)/(5^20 . 3^10)`.
`= 3^10`
`b, (0,8)^5/(0,4)^6 = 2^5/(0,2) = 32/(0,2) = 160`.
`c, (2^15 . 3^28)/(2^12 . 3^3)`
`= 2^3 . 3^25`
`d, = (2^40+2^20)/(2^12 +2^22)`
`= (2^20(2^20+1))/(2^12(1+2^10))`
`= (2^8(2^20+1))(1+2^10)`.
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