\(\text{A}=1+\frac{3}{2^3}+\frac{4}{2^4}+\frac{5}{2^5}+...+\frac{100}{2^{100}}\)
\(\frac{1}{2}.\text{A}=\frac{1}{2}+\frac{3}{2^4}+\frac{4}{2^5}+...+\frac{99}{2^{100}}+\frac{100}{2^{101}}\)
\(=\left[\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{100}}\right]-\frac{100}{2^{101}}\left(\text{do}\frac{3}{2^3}=\frac{1}{2^2}+\frac{1}{2^3}\right)\)
\(=\frac{\left[1-\left(\frac{1}{2}\right)^{101}\right]}{\left(1-\frac{1}{2}\right)}-\frac{100}{2^{101}}\)
\(=\frac{\left(2^{101}-1\right)}{2^{100}}-\frac{100}{2^{101}}\)
\(\Rightarrow\text{A}=\frac{\left(2^{101}-1\right)}{2^{99}}-\frac{100}{2^{101}}\)
P/s: Sai đâu thì bn sửa nhé.
mk cx ko bt đúng hay sai nhưng cx cho bn k