722/24 = 216
(-7,5)3/(2,5)3 = 27
153/27 = 125
722/24 = 216
(-7,5)3/(2,5)3 = 27
153/27 = 125
?4:tinh
\(\frac{72^2}{24^2}\)
\(\frac{\left(-7,5\right)^3}{\left(2,5\right)^3}\)
\(\frac{15^3}{27}\)
4.Tinh
a,\(\frac{4^{30}.3^{43}}{2^{53}.27^{15}}\)
b,\(\frac{\left(-27\right)^{10}.16^{25}}{6^{30}.\left(-32\right)^{15}}\)
c,\(\left(\frac{-2}{17}\right)^3.\left(\frac{-17}{35}\right)^3.\left(\frac{35}{3}\right)^3\)
d,\(\frac{3^{31}.25^8-9^{14}.5^{15}}{27^{10}.5^{15}-3^{30}.5^{17}}\)
e,\(2^{^2}+4^{^2}+6^2+..........+24^2\left(1^2+2^2+3^2+....+12^2=650\right)\)
\(\frac{^{\left(-7,5\right)^3}}{\left(2,5\right)^3}\)
Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
Giai giup mk
a) (-2,5) . (-7,5) . (-4)
b)\(1\frac{4}{23}+\frac{8}{21}-\frac{4}{23}+0,6+\frac{13}{21}\)
c)\(\frac{2}{7}.15\frac{1}{3}-\frac{2}{7}.20\frac{1}{3}+4\frac{1}{3}\)
d)\(2\frac{1}{4}:\left(\frac{-3}{5}\right)-1\frac{1}{4}:\left(\frac{-3}{5}\right)\)
TÌM GTLN HOĂC GTNN :
A = | 4x - 3 | + | 5y + 7,5 | + 10
B = \(\frac{5,8}{\left|2,5-x\right|+5,8}\)
C = 2 + \(\frac{12}{3\left|x+5\right|+4}\)
D = 6 - \(\frac{10}{5\left|6y-8\right|+1}\)
E = - 6 +\(\frac{24}{2\left|x-2y\right|+3\left|2x+1\right|}\)
GIẢI GIÚP MK NHÉ ! LÀM ĐC PHẦN NÀO THÌ LÀM !
a) A=\(\left(\frac{-5}{11}\right).\frac{7}{15}.\left(\frac{11}{-5}\right).\left(-30\right)\)
b) B=\(\left(-\frac{1}{6}\right).\left(\frac{-15}{19}\right).\left(\frac{38}{45}\right)\)
c) C= \(\left(\frac{-5}{9}\right).\frac{3}{11}+\left(\frac{-13}{18}\right).\frac{3}{11}\)
d) D= \(\left(2\frac{2}{15}.\frac{9}{17}.\frac{3}{32}\right):\left(\frac{-3}{27}\right)\)
Tính;
a, \(27^3:3^2\)
b, \(\left(\frac{3}{5}\right)^{15}:\left(\frac{9}{25}\right)^5\)
c, \(5-\left(-\frac{5}{11}\right)^0+\left(\frac{1}{3}\right)^2:3\)
d, \(2^3+3\left(\frac{1}{2}\right)^0+\left[\left(-2\right)^2:\frac{1}{2}\right]\)
\(F=\frac{\left(\frac{53}{4}-2\frac{5}{27}-\frac{65}{6}\right).\left(230+\frac{1}{25}\right)+46\frac{3}{4}}{\left(\frac{24}{7}+3\frac{1}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
giúp mình nhé các bạn