Tuyển Cộng tác viên Hoc24 nhiệm kì 26 tại đây: https://forms.gle/dK3zGK3LHFrgvTkJ6
Bài làm :
\(\frac{4^6\times9^5+120\times6^9}{8^4\times3^{12}-6^{11}}\)
\(=\frac{\left(2^2\right)^6\times\left(3^2\right)^5+2^3\times5\times3\times\left(2\times3\right)^9}{\left(2^3\right)^4\times3^{12}-\left(2\times3\right)^{11}}\)
\(=\frac{2^{12}\times3^{10}+2^3\times5\times3\times2^9\times3^9}{2^{12}\times3^{12}-2^{11}\times3^{11}}\)
\(=\frac{2^{12}\times3^{10}\times\left(1+5\right)}{2^{11}\times3^{11}\times\left(2\times3-1\right)}\)
\(=\frac{2\times6}{3\times5}\)
\(=\frac{4}{5}\)
Học tốt nhé
Rút gọn
\(\frac{4^5\times9^4-2\times6^9}{2^{10}\times3^8+6^8\times20}\)
\(\frac{4^6\times9^5+6^9\times120}{-8^4\times3^{12}-6^{11}}\)help me
Tính nhanh: \(D=\frac{4^6\times9^5+6^9\times120}{-8^4\times3^{12}-6^{11}}\)
\(\frac{4^6\times9^5+6^9\times120}{8^4\times3^{12}-6^{11}}\)
Tính
\(\frac{\left(-0,25\right)^{-5}\times9^4\times\left(-2\right)^{-3}-2^{-2}\times6^9}{2^9\times3^6+6^6\times40}\)
Tính:
\(\frac{2^{12}\times3^5-4^6\times9^2}{12^6+8^4\times3^5}-\frac{5^{10}\times7^3-25^5\times49^2}{\left(125\times7\right)^3+5^9\times14^3}\)
thực hiện phép tính:\(A=\frac{2^{12}\times4^6\times9^2}{2^{12}\times3^6+8^4\times3^5}-\frac{5^{10}\times7^3-25^2\times49^2}{125^3\times7^3+5^9\times14^3}\)
Các bạn ơi ,giúp mình với
Bài 1:Rút gọn
a)\(\frac{2^{19}\times27^3+15\times4^9\times9^4}{6^9\times2^{10}+12^{10}}\)
b)\(\frac{\left(\frac{-1}{2}\right)^3-\left(\frac{3}{4}\right)^3\times\left(-2\right)^2}{2\times\left(-1\right)^5+\left(\frac{3}{4}\right)^2-\frac{3}{8}}\)
c)\(\frac{45\times9^4-2\times6^4}{2^{19}\times3^8+6^8\times20}\)
Bài 2:Tìm x
a)\(5^x+5^{x+2}=650\)
b)\(3^{x-1}+5\times3=162\)
So sánh \(A\) và \(B\) , biết rằng:
\(A=\sqrt[13]{12\times\left(11-\frac{\frac{\left(10\times8\right)^{\left(9+8\right)}}{8}+\frac{6^7\times6-6}{6}}{\frac{5}{4}}\right)\div3+2}\)
\(B=\sqrt[13]{12\div\left(11+\frac{\frac{\left(10\times8\right)^{\left(9-8\right)}}{8}+\frac{6^7\times6+6}{6}}{\frac{5}{4}}\right)\times3-2}\)