Question

Tính cách thuận tiện nhất

\(\dfrac{17}{2}\)x\(\dfrac{3}{5}\)+\(\dfrac{3}{5}\)x\(\dfrac{1}{2}\)+\(\dfrac{3}{5}\)

Answer 1

`17/2 xx 3/5+3/5xx1/2+3/5`

`=3/5xx(17/2+1/2+1)`

`=3/5xx10`

`=30/5=6`

Answer 2

$\dfrac{17}{2}$ \(\times\) $\dfrac{3}{5}$ + $\dfrac{3}{5}$ \(\times\) $\dfrac{1}{2}$ + $\dfrac{3}{5}$

= $\dfrac{3}{5}$ \(\times\) ($\dfrac{17}{2}$ + $\dfrac{1}{2}$) + $\dfrac{3}{5}$

= $\dfrac{3}{5}$ \(\times\) ($\dfrac{17+1}{2}$) + $\dfrac{3}{5}$

= $\dfrac{3}{5}$ \(\times\) $\dfrac{18}{2}$ + $\dfrac{3}{5}$

= $\dfrac{3}{5}$ \(\times\) 9 + $\dfrac{3}{5}$

= $\dfrac{3\(\times\)9}{5}$ + $\dfrac{3}{5}$

= $\dfrac{27}{5}$ + $\dfrac{3}{5}$

= $\dfrac{27+3}{5}$

= $\dfrac{30}{5}$

=6.

Answer 3

\(\dfrac{17}{2}\times\dfrac{3}{5}+\dfrac{3}{5}\times\dfrac{1}{2}+\dfrac{3}{5}\times1\\ =\left(\dfrac{17}{2}+\dfrac{1}{2}+1\right)\times\dfrac{3}{5}\\ =10\times\dfrac{3}{5}\\ =6\)