\(\frac{808}{909}+\frac{111}{333}+\left(-\frac{202}{303}\right)\)
\(=\frac{8}{9}+\frac{1}{3}-\frac{2}{3}\)
\(=\frac{8}{9}+\frac{3}{9}-\frac{6}{9}\)
\(=\frac{5}{9}\)
\(\frac{808}{909}+\frac{111}{333}+\frac{-202}{303}\)
\(=\frac{8}{9}+\frac{1}{3}+\frac{-2}{3}=\frac{8}{9}+\frac{1+(-2)}{3}=\frac{8}{9}+\frac{-1}{3}=\frac{24+(-9)}{27}=\frac{15}{27}=\frac{5}{9}\)