\(3\cdot\frac{1}{4}+\frac{1}{12}\cdot\frac{1}{4}+\frac{35}{12}\cdot\frac{1}{4}\)
\(=(3+\frac{1}{12}+\frac{35}{12})\cdot\frac{1}{4}\)
\(=(3+\frac{36}{12})\cdot\frac{1}{4}\)
\(=(3+3)\cdot\frac{1}{4}\)
\(=6\cdot\frac{1}{4}=\frac{6}{4}\)
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