\(\frac{3}{4}\cdot\frac{2}{5}-\frac{3}{4}\cdot\frac{2}{7}\\ =\frac{6}{20}-\frac{6}{28}\\ =\frac{3}{35}\)
\(\frac{3}{4}\cdot\frac{2}{5}-\frac{3}{4}\cdot\frac{2}{7}\\ =\frac{3}{4}\cdot\left(\frac{2}{5}-\frac{2}{7}\right)\\ =\frac{3}{4}\cdot\frac{4}{35}=\frac{3}{35}\)