Tính A= \(\frac{1^2}{1^2-100+5000}+\frac{2^2}{2^2-200+5000}+...+\frac{99^2}{99^2-9900+5000}\)
Tính A=\(\frac{1^2}{1^2-100+5000}+\frac{2^2}{2^2-200+5000}+\frac{3^2}{3^2-300+5000}+...+\frac{99^2}{99^2-9900+5000}\)
Mong các bạn giúp mình. Ai làm được bài này chắc IQ cao lắm đây.
Tính :
\(\frac{1^2}{1^2-100.1+5000}+\frac{2^2}{2^2-100.2+500}+...+\frac{99^2}{99^2-100.99+5000}\)
Tính
a)B=\(\frac{1+2+2^2+2^3+...+2^{2008}}{1-2^{2009}}\)
b)A=1+2+3+4+5+...+99+100
B=\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{9900}\)
Tính: A = \(1\frac{1}{2}+2\frac{1}{6}+...+99\frac{1}{9900}\)
A=1+2+3+4+5+...+99+100
B=\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+...+\frac{1}{9900}\)
Chứng tỏ giúp mình với !
\(\frac{200-\left(3+\frac{2}{3}+\frac{2}{4}+\frac{2}{5}+...+\frac{99}{100}\right)}{\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+...+\frac{99}{100}}=2\)
Tính nhanh :
A = \(\left(\frac{2}{3}+\frac{3}{4}+....+\frac{99}{100}\right)\cdot\left(\frac{1}{2}+\frac{2}{3}+\frac{3}{4}+....+\frac{98}{99}\right)-\left(\frac{1}{2}+\frac{2}{3}+...+\frac{99}{100}\right)\cdot\left(\frac{2}{3}+\frac{3}{4}+...+\frac{98}{99}\right)\)
tính
a)A=2^3+2^4+2^6+...+2^1000
b)B=7+7^2+7^3+...+7^5000
c)C=4^1+4^3+4^5+...+4^99
