Ta có :
4/1 . 5 + 4/5 . 9 + ...+ 4/2001 . 2005
= 1 - 1/5 + 1/5 - 1/9 + ...+ 1/2001 - 1/2005
= 1 - 1/2005
= 2004/2005
Tham khảo nha !!!
Đặt A=\(\frac{4}{1\cdot5}+\frac{4}{5\cdot9}+...+\frac{4}{2001\cdot2005}\)
\(\Rightarrow A=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+...+\frac{1}{2001}-\frac{1}{2005}\)
\(\Rightarrow A=1-\frac{1}{2005}\)
\(\Rightarrow A=\frac{2004}{2005}\)
Ta có
\(\frac{4}{1\cdot5}+\frac{4}{5\cdot9}+...+\frac{4}{2001\cdot2005}\)
\(=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+...+\frac{1}{2001}-\frac{1}{2005}\)
\(=1-\frac{1}{2005}\)
\(=\frac{2004}{2005}\)
Đặt \(A=\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{1}{2001.1005}\)
\(\Rightarrow A=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{2001}-\frac{1}{2005}\)
\(\Rightarrow A=1-\frac{1}{2005}\)
\(\Rightarrow A=\frac{2004}{2005}\)