17 + (x - 7) + 2(2x + 1) = 17
<=> x - 7 + 2(2x + 1) = 17 - 17
<=> x - 7 + 2(2x + 1) = 0
<=> x + 2(2x + 1) = 0 + 7
<=> x + 2(2x + 1) = 7
<=> x + 4x + 1 = 7
<=> 5x + 2 = 7
<=> 5x = 7 - 2
<=> 5x = 5
=> x = 1
\(17+\left(x-7\right)+2\left(2x+1\right)=17\)
\(\Rightarrow x-7+4x+2=0\)
\(\Rightarrow5\left(x-1\right)=0\)
\(\Rightarrow x-1=0\)
\(\Rightarrow x=1\)
\(17+\left(x-7\right)+2\left(2x+1\right)=17\)
\(\Leftrightarrow17+x-7+4x+2=17\)
\(\Leftrightarrow\left(17-7\right)+\left(x+2x\right)+2=17\)
\(\Leftrightarrow10+3x+2=17\)
\(\Leftrightarrow\left(10+2\right)+3x=17\)
\(\Leftrightarrow12+3x=17\)
\(\Leftrightarrow3x=17-12\)
\(\Leftrightarrow3x=5\)
\(\Leftrightarrow x=\frac{5}{3}\)
\(17+\left(x-7\right)+2.\left(2x+1\right)=17\)
\(\Rightarrow17+x-7+4x+2=17\)
\(\Rightarrow x-7+4x+2=17-17\)
\(\Rightarrow x-7+4x+2=0\)
\(\Rightarrow5x-5=0\)
\(\Rightarrow5x=0+5=5\)
\(\Rightarrow x=5:5=1\)
Vậy x = 1