Question

tìm x,y,z thuộc Z:

-6:4=x:(-28)=15:y=z:36

Answer 1

Theo bài ra ta có

• \(\frac{-6}{4}=\frac{x}{-28}=>x=\frac{\left(-6\right).\left(-28\right)}{4}=\frac{168}{4}=42\)

• \(\frac{-6}{4}=\frac{15}{y}=>y=\frac{15}{\frac{-6}{4}}=\frac{15.4}{-6}=\frac{60}{-6}=-10\)

• \(\frac{-6}{4}=\frac{z}{36}=>z=\frac{36.\left(-6\right)}{4}=\frac{-216}{4}=-54\)

Vậy (x;y;z) là (42;-10;-54)

Answer 2

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