ĐKXĐ:\(x\ge0,y\ge1\)
\(x-4\sqrt{x}+y-6\sqrt{y-1}+z=0\)
\(\Leftrightarrow x-4\sqrt{x}+4+y-1-6\sqrt{y-1}+9+z-12=0\)
\(\Leftrightarrow\left(\sqrt{x}-2\right)^2+\left(\sqrt{y-1}-3\right)^2+z-12=0\)
\(\Leftrightarrow\hept{\begin{cases}\left(\sqrt{x}-2\right)^2=0\\\left(\sqrt{y-1}-3\right)^2=0\\z-12=0\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=4\\y=10\\z=12\end{cases}}\)(THỎA MÃN ĐKXĐ)
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