Question

Tìm x,y

(2x-5)^2016 + (3y+4)^2018 <=0

 

Answer 1

\(\left(2x-5\right)^{2016}+\left(3y+4\right)^{2018}\le0\)

\(\Leftrightarrow\hept{\begin{cases}2x-5=0\\3y+4=0\end{cases}}\)

\(\Leftrightarrow\hept{\begin{cases}x=\frac{5}{2}\\y=-\frac{4}{3}\end{cases}}\)