tim x;y;z biet x(x+y+z)=2; y(x+y+z)=25; z(x+y+z)=-2; x>0
Tim x, y, z biet
a ) |x-3,5|+ |x+5|=0
b) |x-1| + (y+1)^2 + |z-1|=0
c) ( x-1/3)^2 + (y-2)^2+ (z-1)^2 be hon hoac bang 0
d)(x-z)^2+ (y+x)^2 + (z+1/4)^2 =0
Cac ban giup minh voi minh can gap lam
tim x y z biet
a) x.(y-2).(x^2-9)=0
Tim x, y, z biet x, y, z > 0 , x-y/z = y-z/x = z-x/y va x+2y+3z=30
tim x ; y ; z biet |x+y-2,8|+ |y+z+4|+ |z+x-1/4|=0
Tim x,y,z biet: a,(3x−2y)6+(y−5z)8+|z−2|=0(3x−2y)6+(y−5z)8+|z−2|=0
b,3x−2y4=2x−4z3=y−3z23x−2y4=2x−4z3=y−3z2va x+y+z=990
Gấp gấp gấp!
Tim x,y,z biet: a,(3x−2y)6+(y−5z)8+|z−2|=0(3x−2y)6+(y−5z)8+|z−2|=0
b,3x−2y4=2x−4z3=y−3z23x−2y4=2x−4z3=y−3z2va x+y+z=990
Gấp gấp gấp!
x/-2=9/y=3-2z/5
x+z=0
Tim y
a, tim x,y,z biet |x-1/2| +|y+2/3| +x2+xz| =0
\(\sqrt{\left(x-2\right)^2}+\sqrt{\left(y+2\right)^2}+\left|x+y+z\right|=0\)
tim x,y,z
