Question

Tìm x,y    (x-0,5)^2+(y+0,25)^2=0

Answer 1

\(\left(x-0,5\right)^2+\left(y+0,25\right)^2=0\)

Do \(\hept{\begin{cases}\left(x-0,5\right)^2\ge0\\\left(y+0,25\right)^2\ge0\end{cases}\Rightarrow VT\ge0}\)

Dấu "=" xảy ra \(\Leftrightarrow\hept{\begin{cases}x-0,5=0\\y+0,25=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=0,5\\y=-0,25\end{cases}}}\)

Vậy \(\hept{\begin{cases}x=0,5\\y=-0,25\end{cases}}\)

Answer 2

vì \(\hept{\begin{cases}\left(x-0,5\right)^2\ge0\\\left(y+0,25\right)\ge0\end{cases}}\)

mà \(\left(x-0,25\right)^2+\left(y-0,25\right)^2=0\)

\(\Rightarrow\hept{\begin{cases}\left(x+0,5\right)^2=0\\\left(y-0,25\right)^2=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x+0,5=0\\y-0,25=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=-0,5\\y=0,25\end{cases}}\)

Answer 3

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