xét:\(\frac{1+2y}{18}=\frac{1+6y}{6x}=\frac{1+2y+1+6y}{18+6x}=\frac{2+8y}{18+6x}=\frac{2\left(1+4y\right)}{2.\left(9+3x\right)}=\frac{1+4y}{9+3x}\)
ta có:\(\frac{1+4y}{24}=\frac{1+4y}{9+3x}\Rightarrow9+3x=24\Rightarrow3x=15=>x=5\)
vậy x=5
tick nhé
Tìm x, y thỏa mãn \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
tìm x,y biết
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Tìm x,y,z biết:
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Tìm x,y biết \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Tìm x,y
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Tìm x;y biết: \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Tìm x,y,z biết: \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Tìm x : \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Tìm x, y biết: \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)