Question

tìm x

(x+1)+(x+2)+(x+3)+...+(x+100)=5750

Answer 1

Phá ngoặc

x + 1 + x + 2+  .... + x + 100 = 5750

100x + 100.101:2 = 5750

100x + 5050 = 5750

100x = 5750 - 5050 = 700

x = 700 : 100 = 7

Answer 2

=> x + 1 + x + 2 + ... + x + 100 = 5750

=> 100x + (1+2+...+100) = 5750

=> 100x + \(\frac{\left(100+1\right).100}{2}\) = 5750

=> 100x +5050 = 5750 

=> 100x = 5750 - 5050

=> 100x = 700

=> x = 7

Answer 3

( x + x + ... + x ) + ( 1 + 2 + ... + 100 ) = 5750

           100.x      +              5050         = 5750

            100.x                                     = 700

                  x                                     = 700 : 100

                  x                                     = 7

tick nha

Answer 4

(x+x+x+....+x)+(1+2+3+...+100)=5750

100.x+5050+5750

100.x=5750-5050

100.x=700

x=700:10

x=7

vay x =7

 

Answer 5

(x+x+..+x)+(1+2+...+100)=5750

x.100+5050+5750

x.100=5750-5050=700

x=700:100

x=7

Answer 6

x+1x+2x+3+...+x+100=5750

x*{1+2+3+...+100}=5750

x*{100-1:1+1}=5750

x*100=5750

x=5750:100

x=57,5