Question

tim x

(x+1)^2=(x+1)^0

(3^x-4).(x-3)^3=0

 

 

Answer 1

\(\left(3x-4\right)\left(x-3\right)^3=0\)

\(=>\orbr{\begin{cases}3x-4=0\\x-3=0\end{cases}=>\orbr{\begin{cases}x=\frac{4}{3}\\x=3\end{cases}}}\)

Ủng hộ nha

Answer 2

a) \(\left(x+1\right)^2=\left(x+1\right)^0\)

\(=>\left(x+1\right)^2=1\)

\(=>\orbr{\begin{cases}x+1=-1\\x+1=1\end{cases}}\)

\(=>\orbr{\begin{cases}x=-2\\x=0\end{cases}}\)