Question

Tìm x:

(x-4)²-48=-12

 

Answer 1

\(\left(x-4\right)^2-48=-12\) 

\(\left(x-4\right)^2=-12+48\)

\(\left(x-4\right)^2=36\)

\(\left(x-4\right)^2=6^2\) 

\(\Rightarrow x-4=6\)

\(\Rightarrow x=6+4\)

\(\Rightarrow x=10\)

Answer 2

(x-4)²-48=-12

(x-4)^{2=  (-12 ) +48}

(x-4)^{2= 36}

36 = 6²

^{=> x - 4 = 6}

^{x = 6 +4}

^{x = 10}

Answer 3

(x-4)^2=48-12=0=>(x-4)^2=36=> x-4=6 hoặc x-4=-6 => x=10 hoặc x=-2

vậy ...

Answer 4

\((x-4)^2-48=-12\)

\(\Rightarrow(x-4)^2=-12+48\)

\(\Rightarrow(x-4)^2=36\)

\(\Rightarrow(x-4)^2\pm36\)

\(\Rightarrow\hept{\begin{cases}(x-4)^2=6^2\\(x-4)^2=(-6)^2\end{cases}}\Rightarrow\hept{\begin{cases}x-4=6\\x-4=-6\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=10\\x=-2\end{cases}}\)

Vậy : ....

Answer 5

\(\left(x-4\right)^2-48=-12\)

\(\left(x-4\right)^2=-12+48\)

\(\left(x-4\right)^2=36\)

\(\left(x-4\right)^2=6^2\)

\(x-4=6\)

Xét 2 trường hợp: 

TH1: x - 4 = 10

         x      = 6 + 4

         x      = 10

TH2: x - 4 = -6

         x      = -6 + 4

         x      = -2

Tự kl :<

Answer 6

\(\left(x-4\right)^2-48=-12\)

\(\left(x-4\right)^2=\left(-12\right)+48\)

\(\left(x-4\right)^2=36\)

\(\left(x-4\right)^2=6^2\)

\(\Rightarrow x-4=6\)

\(\Rightarrow x=6+4\)

\(\Rightarrow x=10\)