Question

tìm x

p)   135 – 5(x + 4) = 35
q)   25 + 3(x – 8) = 106
r)    32(x + 4) – 52 = 5.22

Answer 1

\(p) 135 - 5(x + 4) = 35 \)

`=> 5(x+4)=135-35`

`=>5(x+4)=100`

`=>x+4=100/5`

`=>x+4=20`

`=>x=20-4`

`=>x=16`

__

\(q) 25 + 3(x - 8) = 106 \)

`=>3(x-8)=106-25`

`=>3(x-8)=81`

`=>x-8=81/3`

`=>x-8=27`

`=>x=27+8`

`=>x=35`

__

\(r) 32(x + 4) - 52 = 5.22 \)

`=>32(x+4)-52=110`

`=>32(x+4)=110+52`

`=>32(x+4)=162`

`=>x+4=162/32`

`=>x+4~~5`

`=>x=5-4`

`=>x=1`

Answer 2

\(p,135-5.\left(x+4\right)=35< =>5.\left(x+4\right)=135-35< =>5.\left(x+4\right)=100< =>x+4=100:5< =>x+4=20< =>x=20-4< =>x=16\)

\(q,25+3.\left(x-8\right)=106< =>3.\left(x-8\right)=106-25< =>3.\left(x-8\right)=81< ->x-8=81:3< =>x-8=27< =>x=27+8< =>x=35\)

\(r,32.\left(x+4\right)-52=5.22< ->32.\left(x+4\right)-52=110< =>32.\left(x+4\right)=110+52< =>32.\left(x+4\right)=162< =>x+4=162:32< =>x+4=\dfrac{81}{16}< =>x=\dfrac{81}{16}-4< =>x=\dfrac{17}{16}\)

Answer 3

⇒ x + 4 = 100 : 5

 

⇒ x - 8 = 81 : 3

 

\(\dfrac{81}{16}\) - 4 

\(\dfrac{17}{16}\)

     Vậy x = \(\dfrac{17}{16}\)

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