Question

tìm x
\(\left(x+2\right).\left(x+3\right)-\left(x-2\right).\left(x+5\right)=0\)

Answer 1

\(x^2+2x+3x+6-\left(x^2-2x+5x-10\right)=0\\ x^2+5x+6-x^2-3x+10=0\\ 2x+16=0\\ 2x=-16\\ x=\left(-16\right):2\\ x=-8\)