Question

tìm x

\(\left[x-2\right]^{^{2016}}\)=\(\left[x-2\right]^{^{2015}}\)

Answer 1

=> x - 2 = 1 

x          = 3

Vậy x = 3

Answer 2

1303656

Answer 3

\(\left(x-2\right)^{2016}=\left(x-2\right)^{2015}\)

\(\Leftrightarrow\left(x-2\right)^{2016}-\left(x-2\right)^{2015}=0\)

\(\Leftrightarrow\left(x-2\right)^{2015}.\left(x-2\right)-\left(x-2\right)^{2015}=0\)

\(\Leftrightarrow\left(x-2\right)^{2015}\left[\left(x-2\right)-1\right]=0\)

\(\Leftrightarrow\left(x-2\right)^{2015}.\left(x-3\right)=0\)

\(\Rightarrow\orbr{\begin{cases}\left(x-2\right)^{2015}=0\\x-3=0\end{cases}\Rightarrow\orbr{\begin{cases}x-2=0\\x-3=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=2\\x=3\end{cases}}}\)