\(\left(x-1\right)^2=49\)
=> \(\left(x-1\right)^2=7^2=\left(-7\right)^2\)
=> \(\orbr{\begin{cases}x-1=7\\x-1=-7\end{cases}}\)
=> \(\orbr{\begin{cases}x=8\\x=-6\end{cases}}\)
KL: x thuộc {8; -6}
bài 1 : tìm x: \(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
bài 2: tìm x : \(\left(8x-1\right)^{2n+1}=5^{2n+1}\)(n thuộc N)
Tìm x
a\ \(\left(x-7\right)^{x+1}-\left(x+7\right)^{x+11}=0\)
b\ \(\left(x-1\right)^2=\frac{36}{49}\)
Tìm x biết
a\ \(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
b\ \(\left(x-1\right)^2=\frac{36}{49}\)
Bài 1:Tìm x
a)\(\left(5x+1\right)^2=\frac{36}{49}\)
b)\(\left(x-\frac{2}{9}\right)^3=\left(\frac{2}{3}\right)^6\)
c)\(\left(8x-1\right)^{2x+1}=5^{2x+1}\)
Tìm x, y:
\(x+\left(\frac{-31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
tìm x ,y biết
\(x+\left(-\frac{3}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
Tìm x;y biết rằng:
\(x+\left(-\frac{31}{12}\right)^2=\left(\frac{49}{12}\right)^2-x=y^2\)
b1: rút gọn biểu thức:
\(A=\frac{1-\frac{1}{\sqrt{49}}+\frac{1}{49}-\frac{1}{\left(7.\sqrt{7}\right)^2}}{\frac{\sqrt{64}}{2}-\frac{4}{7}+\left(\frac{2}{7}\right)^2-\frac{4}{343}}\)
b2: tìm x, y, z thỏa mãn:
\(\sqrt{\left(x-\sqrt{2}\right)^2}_{ }\)+ \(\sqrt{\left(y+\sqrt{2}\right)^2}^{ }\)+ |x+y+z| = 0
nhanh nhé, ai đúng mk t*** cho !!!
Tìm giá trị x thỏa mãn:
a, \(\dfrac{x+1}{2}\) và \(\dfrac{2}{x+1}\)
b, \(\dfrac{\left(x-2\right)^2}{7}\) = \(\dfrac{49}{x-2}\)
Help me pls! (vì đang cần gấp :V)