Question

tìm x

\(\left(\dfrac{2}{3}-\dfrac{1}{4}\right)^{x-2}=1\)

Answer 1

\(\left(\dfrac{2}{3}-\dfrac{1}{4}\right)^{x-2}=1\)

\(\dfrac{5}{12}^{x-2}=1\)

\(\dfrac{5}{12}^{x-2}=\dfrac{5}{12}^0\)

\(x-2=0\)

\(x=0+2\)

\(x=2\)

Answer 2

\(\left(\dfrac{2}{3}-\dfrac{1}{4}\right)^{x-2}=1\)

\(\left(\dfrac{8}{12}-\dfrac{3}{12}\right)^{x-2}=1\)

\(\left(\dfrac{5}{12}\right)^{x-2}=1\)

\(\left(\dfrac{5}{12}\right)^{x-2}=\left(\dfrac{5}{12}\right)^0\)

`=> x-2=0`

`x=0+2`

`x=2`

Vậy `x=2`

Answer 3

\(\left(\dfrac{2}{3}-\dfrac{1}{4}\right)^{x-2}=1\)

\(\left(\dfrac{8}{12}-\dfrac{3}{12}\right)^{x-2}=1\)

\(\left(\dfrac{5}{12}\right)^{x-2}=1\)

`=>`\(\left(\dfrac{5}{12}\right)^{x-2}=\left(\dfrac{5}{12}\right)^0\)

`=>x-2=0`

`x=0+2`

`x=2`