ĐKXĐ : \(x\ge-1\)
\(\sqrt{x+1}+\sqrt{x+6}=5\) \(\Leftrightarrow\sqrt{x+1}-2+\sqrt{x+6}-3=0\)
\(\Leftrightarrow\dfrac{x-3}{\sqrt{x+1}+2}+\dfrac{x-3}{\sqrt{x+6}+3}=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\\dfrac{1}{\sqrt{x+1}+2}+\dfrac{1}{\sqrt{x+6}+3}=0\left(PTVN\right)\end{matrix}\right.\)
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