Tìm x:\(a,\frac{6x-5}{-7}=\frac{5x-3}{-5}\\ b,\frac{12-7x}{-13}=\frac{4-3x}{-5}\\ c,\frac{2x+4}{7}=\frac{4x-2}{15}\)
Tìm x
c, \(\frac{3x-5}{2x+1}=\frac{6x-7}{4x-3}\)
d,\(\frac{x-1}{4}=\frac{9}{x-1}\)
nói cách làm nữa nhé
Tìm x
c, \(\frac{3x-5}{2x+1}=\frac{6x-7}{4x+3}\)
d, \(\frac{x-1}{4}=\frac{9}{x-1}\)
nói cách làm nữa nhé
Tim so huu ti x
a)\(\frac{2}{3x}-\frac{3}{12}=\frac{4}{5}-\left(\frac{7}{x}-2\right)\))
b)\(\frac{1}{x-1}+\frac{-2}{3}\left(\frac{3}{4}-\frac{6}{5}\right)=\frac{5}{2-2x}\)
c)\(3-\frac{2}{2x-3}=\frac{2}{5}+\frac{2}{9-6x}-\frac{3}{2}\)
e)\(\frac{x}{2}-\frac{1}{x}=\frac{1}{12}\)
Tìm x,y,z, biết \(\frac{2x+1}{5}=\frac{3x-2}{7}=\frac{z+4}{9}=\frac{2x+3y-1}{6x}\)
Bài 1 Tìm x,y biết:
a,x+y=2(y-x)=\(3\frac{x}{y}\) (y khác 0)
b,\(\frac{5-3x}{7-2x}\)=\(\frac{6x-4}{1+4x}\)
c,|2x+1|-5(3-2x)=2
Tìm x thuộc Z sao cho có giá trị nguyên
\(A=\frac{x^2-10x+36}{x-5}\)
\(B=\frac{2x^2+3x+3}{2x-1}\)
\(C=\frac{4x^2-6x-7}{x-3}\)
\(D=\frac{2x^2+x+6}{x+3}\)
\(E=\frac{3x^3+10x-5}{3x+1}\)
\(\frac{x-1}{12}+\frac{2x-3}{23}+\frac{3x-5}{34}+\frac{4x-7}{45}-4\)
Tìm x biết
a,\(\left(\frac{4}{5}\right)^{2x+7}\text{=}\frac{625}{256}\)
b,\(\frac{7^{x+2}+7^{x+1}+7^x}{57}\text{=}\frac{5^{2x}+5^{2x+1}+5^{2x+3}}{131}\)
c,\(\left(4x-3\right)^4\text{=}\left(4x-3\right)^2\)
d,\(\frac{2x+3}{5x+2}\text{=}\frac{4x+5}{10x+2}\)
e,\(\frac{3x-1}{40-5x}\text{=}\frac{2x-3x}{5x-34}\)
f,\(\frac{15}{x-9}\text{=}\frac{20}{y-12}\text{=}\frac{40}{z-2x}\) và \(xy\text{=}1200\)
