AA

Tìm \(x:\)\(\frac{24,3}{x+16}=\frac{40,8}{x+71}\)

\(\frac{24,3}{x+16}=\frac{40,8}{x+71}\)

\(\Rightarrow\left(x+71\right).24,3=\left(x+16\right).40,8\)

\(\Rightarrow24,3x+1725,3=40,8x+652,8\)

\(\Rightarrow16,5x=1072,5\)

\(\Rightarrow x=65\)

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