Ta có :\(\frac{x+8}{12}+\frac{x+9}{11}+\frac{x+10}{10}+3=0\)
=> \(\left(\frac{x+8}{12}+1\right)+\left(\frac{x+9}{11}+1\right)+\left(\frac{x+10}{10}+1\right)=0\)
=> \(\frac{x+20}{12}+\frac{x+20}{11}+\frac{x+20}{10}=0\)
=> \(\left(x+20\right)\left(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\right)=0\)
Vì \(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\ne0\)
=> x + 20 = 0
=> x = -20
Vậy x = -20
\(\frac{x+8}{12}+\frac{x+9}{11}+\frac{x+10}{10}+3=0\)
\(\Leftrightarrow\left(\frac{x+8}{12}+1\right)+\left(\frac{x+9}{11}+1\right)+\left(\frac{x+10}{10}+1\right)=0\)
\(\Leftrightarrow\frac{x+20}{12}+\frac{x+20}{11}+\frac{x+20}{10}=0\)
\(\Leftrightarrow\left(x+20\right)\left(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\right)=0\)
Vì \(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\ne0\)
\(\Rightarrow x+20=0\Rightarrow x=-20\)
cái bên vế phải chả hiểu là j ?? Tớ tạm đặt là \(\alpha\) nhé ( \(\alpha\)là 1 hằng số )
pt <=> \(\left(\frac{x+8}{12}+1\right)+\left(\frac{x+9}{11}+1\right)+\left(\frac{x+10}{10}+1\right)=\alpha\)
<=> \(\frac{x+20}{12}+\frac{x+20}{11}+\frac{x+20}{10}=\alpha\)
<=> \(\left(x+20\right)\left(\frac{1}{12}+\frac{1}{11}+\frac{1}{10}\right)=\alpha\)
<=> \(\frac{\left(x+20\right).181}{660}=\alpha\)
<=> \(x=\frac{660\alpha}{181}-20\)
Bạn tự thay \(\alpha\)là 1 số nào tùy ý cũng sẽ tìm ngay ra x thôi
