\(2015-\left|x-2015\right|=x\)
\(\Leftrightarrow\left|x-2015\right|=2015-x\)
\(\Leftrightarrow\orbr{\begin{cases}x-2015=2015-x\\x-2015=-\left(2015-x\right)\end{cases}}\)
\( TH1:x-2015=2015-x\)
\(\Leftrightarrow2x=4030\)
\(\Leftrightarrow x=\frac{4030}{2}\)
\(\Leftrightarrow x=2015\)
\(TH2:x-2015=-\left(2015-x\right)\)
\(\Leftrightarrow x-2015=x-2015\)
Vậy x = 2015
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